Question

7а(4а-9)-(14а-5)(2а-3)

Answer 1

Ответ:

-11a-15

Объяснение:

28a^2-63a-28a^2+42a+10a-15=-11a-15

Answer 2

Полностью расписано
28a2-63a-(28a2-42a-10a+15)
28a2-63a-(28a2-52a+15)
28a2-63a2+52a-15=-11a-15

Answer 3

To simplify the expression 7a(4a-9)-(14a-5)(2a-3), you can use the distributive property (also known as the FOIL method) to expand the products and then combine like terms. Here's the step-by-step simplification:

1. Distribute the 7a into the first binomial (4a-9): 7a * 4a = 28a^2 7a * (-9) = -63a

2. Distribute the -1 into the second binomial (14a-5): -1 * 14a = -14a -1 * (-5) = 5

3. Now, distribute the result of the first distribution (7a) into the second binomial (2a-3): 7a * 2a = 14a^2 7a * (-3) = -21a

4. Distribute the result of the second distribution (-1) into the first binomial (4a-9): -1 * 4a = -4a -1 * (-9) = 9

5. Now, we have the distributed terms: 28a^2 - 63a - 14a + 5 + 14a^2 - 21a - 4a + 9

6. Combine like terms: (28a^2 + 14a^2) + (-63a - 14a - 21a - 4a) + (5 + 9)

7. Combine the like terms in each group: 42a^2 - 102a + 14

So, the simplified expression is 42a^2 - 102a + 14.