Question

(2b+5)²-(2b-3)(3b+5)​

Answer 1

Ответ:

$(2b + 5) {}^{2} - (2b - 3)(3b + 5) = 4b {}^{2} + 20b + 25 - (6b {}^{2} + 10b - 9b - 15) = 4b {}^{2} + 20b + 25 - 6b {}^{2} - b + 15 = - 2b {}^{2} + 19b + 40.$

Объяснение:

★ (a+b)²=a²+2ab+b² ★

Answer 2

To simplify the expression (2b + 5)² - (2b - 3)(3b + 5), you can follow these steps:

Step 1: Expand (2b + 5)²: (2b + 5)² = (2b + 5)(2b + 5) Using the FOIL (First, Outer, Inner, Last) method to multiply the binomials: = (2b * 2b) + (2b * 5) + (5 * 2b) + (5 * 5) = 4b² + 10b + 10b + 25 = 4b² + 20b + 25

Step 2: Expand (2b - 3)(3b + 5) using the FOIL method: (2b - 3)(3b + 5) = (2b * 3b) + (2b * 5) + (-3 * 3b) + (-3 * 5) = 6b² + 10b - 9b - 15 = 6b² + b - 15

Step 3: Subtract the result of step 2 from the result of step 1: (4b² + 20b + 25) - (6b² + b - 15)

Now, perform the subtraction: = 4b² + 20b + 25 - 6b² - b + 15

Step 4: Combine like terms: (4b² - 6b²) + (20b - b) + (25 + 15) = -2b² + 19b + 40

So, the simplified expression is -2b² + 19b + 40.