Question

A) x² + 7x+12=0; б) x2 - 2x - 35=0; Помогите пж ​

Answer 1

Ответ:

1) х= -3; -4

2) х= 7; -5

Объяснение:

1) х^2 + 7х + 12 = 0

Д= 7^2 - 4*1*12= 49-48= 1

корень из Д= 1

х1= (-7+1)/2= -3

х2= (-7-1)/2= -4

2) х^2 - 2х - 35 = 0

Д=2^2 + 4*1*35= 4+140= 144

корень из Д= 12

х1= (2+12)/2= 7

х2= (2-12)/2= -5

Answer 2

A) To solve the equation x² + 7x + 12 = 0, we can use the quadratic formula. The quadratic formula states that for an equation in the form ax² + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 1, b = 7, and c = 12. Substituting these values into the quadratic formula, we get:

x = (-7 ± √(7² - 4(1)(12))) / (2(1))

Simplifying further:

x = (-7 ± √(49 - 48)) / 2

x = (-7 ± √1) / 2

x = (-7 ± 1) / 2

So the solutions to the equation x² + 7x + 12 = 0 are:

x₁ = (-7 + 1) / 2 = -3

x₂ = (-7 - 1) / 2 = -6

B) To solve the equation x² - 2x - 35 = 0, we can again use the quadratic formula. In this case, a = 1, b = -2, and c = -35. Substituting these values into the quadratic formula, we get:

x = (-(-2) ± √((-2)² - 4(1)(-35))) / (2(1))

Simplifying further:

x = (2 ± √(4 + 140)) / 2

x = (2 ± √144) / 2

x = (2 ± 12) / 2

So the solutions to the equation x² - 2x - 35 = 0 are:

x₁ = (2 + 12) / 2 = 7

x₂ = (2 - 12) / 2 = -5

Therefore, the solutions to the equations are: A) x = -3 and x = -6 B) x = 7 and x = -5

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