Question

Велосипед выехал с постоянной скоростью из города А в город В ,расстояние между которыми 165 км.на следующий день он отправился обратно в город В на 18км/ч.по пути он сделал остановку на 6 часов в результате чего затратил на обратный путь столько же времени сколько на путь из А в В.найдите скорость велосипедиста на пути из А в В

Answer 1

Ответ:

Скорость из А в В х Проехал 156/х часов

Скорость из В в А х+1 Проехал 156/(х+1) часов

Разница 156/х - 156/(х+1) = 1

156 - 156 = 1

х __х+1

156(х+1) - 156х = х(х+1)

156 = х2 + х

х2 + х - 156 = 0

D = 12 - 4 ∙ 1 ∙ (-156) = 1 + 624 = 625 = 252

x1 = (-1-25)/2 < 0 не удовлетворяет условию задачи, скорость не может быть отрицательной

x2 = (-1+25)/2 = 24/2 = 12 км/ч

Объяснение:

Answer 2

Problem Analysis

A cyclist travels from city A to city B at a constant speed. The distance between the two cities is 165 km. On the next day, the cyclist returns from city B to city A at a speed of 18 km/h. During the return journey, the cyclist makes a 6-hour stop, resulting in the return journey taking the same amount of time as the journey from A to B. We need to find the speed of the cyclist on the journey from A to B.

Solution

Let's assume the speed of the cyclist on the journey from A to B is x km/h.

To find the time taken for the journey from A to B, we can use the formula:

Time = Distance / Speed

The time taken for the journey from A to B is given by:

Time_AB = 165 km / x km/h

During the return journey, the cyclist travels at a speed of 18 km/h. The time taken for the return journey is given by:

Time_BA = 165 km / 18 km/h

Since the return journey took the same amount of time as the journey from A to B, we can set up the following equation:

Time_AB = Time_BA + 6 hours

Substituting the values, we get:

165 km / x km/h = 165 km / 18 km/h + 6 hours

Simplifying the equation, we can solve for x:

165 / x = 165 / 18 + 6

Now let's calculate the value of x.

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