Question

Помогите пожалуйста срочно!!!!!!!!!!!!!!!!!!!!!!!!!!! В шахматном турнире участвовали 40 шахматистов, каждый сыграл с каждым ровно один раз. За победу давалось 1 очко, за ничью — 1/2, а за поражение — 0. У какого наибольшего числа шахматистов по окончании турнира могло оказаться ровно 7 очков?

Answer 1

Ответ:

20

Объяснение:

лень писать,

Answer 2

Calculation of Maximum Points

To determine the maximum number of points a chess player could have at the end of the tournament, we need to consider the number of games played and the scoring system.

In this tournament, there are 40 chess players, and each player plays against every other player exactly once. This means that each player will play a total of 39 games (since they don't play against themselves).

For each game, there are three possible outcomes: a win, a draw, or a loss. The scoring system assigns 1 point for a win, 1/2 point for a draw, and 0 points for a loss.

To calculate the maximum number of points, we need to consider the best-case scenario for each player. Let's assume that a player wins all their games. In this case, they would score 1 point for each of the 39 games, resulting in a total of 39 points.

Now, let's consider the scenario where a player wins all but one game, which they draw. In this case, they would score 1 point for each of the 38 wins and 1/2 point for the draw, resulting in a total of 38.5 points.

Continuing this pattern, we can see that the maximum number of points a player can have is always an integer or a half-integer. Therefore, the maximum number of points a player can have at the end of the tournament and still have exactly 7 points is 7.0.

This means that it is possible for a chess player to have exactly 7 points at the end of the tournament.