Question

1. Бічна сторона рівнобедреного трикутника ABC дорівнює 9 см, а його периметр 25 см. Знайди основу цього трикутника.​

Answer 1

Відповідь:

Основа трикутника 7 см

Пояснення:

1) 9*2=18(см) - бічні сторони трикутника;

2) 25-18= 7(см) - основа трикутника;

Answer 2

Problem Analysis

We are given that the lateral side of an isosceles triangle ABC is 9 cm and its perimeter is 25 cm. We need to find the base of this triangle.

Solution

Let's assume that the base of the triangle is x cm. Since the triangle is isosceles, the other two sides will also be x cm each.

The perimeter of a triangle is the sum of all its sides. In this case, we have:

x + x + 9 = 25

Simplifying the equation, we get:

2x + 9 = 25

Subtracting 9 from both sides, we have:

2x = 16

Dividing both sides by 2, we get:

x = 8

Therefore, the base of the triangle is 8 cm.

Conclusion

The base of the given isosceles triangle ABC is 8 cm.