Question

Найди корни уравнения: 27n3+ (9 – 3n)(81 + 27п + 9n2) + 10п = 29n=....помогите​

Answer 1

Ответ:

-70

Объяснение:

Проверено в Онлайн мектеп.

Answer 2

Solving the Equation 27n^3 - (9 - 3n)(81 + 27p + 9n^2) + 10p = 29n

To solve the equation 27n^3 - (9 - 3n)(81 + 27p + 9n^2) + 10p = 29n, we'll start by expanding and simplifying the expression.

Expand and Simplify the Equation

Expanding the expression gives us: 27n^3 - (9*81 + 9*27p + 9*9n^2 - 3n*81 - 3n*27p - 3n*9n^2) + 10p = 29n

Simplifying further: 27n^3 - (729 + 243p + 81n^2 - 243n - 81np - 27n^3) + 10p = 29n

Rearranging the terms: 27n^3 - 27n^3 + 81n^2 - 243n + 10p - 81np + 29n - 729 - 243p = 0

Group Like Terms

Combining like terms: 81n^2 - 214n - 81np + 29n - 243p - 729 + 10p = 0

81n^2 - 185n - 81np - 214p - 729 = 0

Solve for n and p

This is a quadratic equation in terms of n and p. We can use the quadratic formula to solve for n and p: n = (-b ± √(b^2 - 4ac)) / (2a) p = (-b ± √(b^2 - 4ac)) / (2a)

Where a = 81, b = -185, and c = -81p - 214p - 729.

By substituting the values of a, b, and c into the quadratic formula, we can solve for n and p.

Let's calculate the discriminant (b^2 - 4ac) to determine the nature of the solutions for n and p.

Calculate the Discriminant

The discriminant is given by: Δ = b^2 - 4ac

Substitute the values of a, b, and c into the formula to calculate the discriminant.

After calculating the discriminant, we can determine the nature of the solutions for n and p based on the value of the discriminant.

I hope this helps! Let's continue with the calculations to solve for n and p.