Question

Мне срочно нужно пж :(

Answer 1

Ответ:

$=(m^{2} -1)*(m^{4} +m^{2} +1-1+3)=3(m^{4} -1)$

$=(m-1)*(m+1)*(m^{4} +m^{2} +3)=3(m-1)*(m+1)*(m^{2} +1)$

=$(m-1)*(m+1)*(m^{4}+m^{2} +3-3(m^{2} +1))=0$

$(m-1)*(m+1)*(m^{4} -2m^{2} )=0$

$m1=-\sqrt{2} \\m2=-1\\m3=0\\m4=1\\m5=\sqrt{2}$

Answer 2

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