Question

Вывесте tga, если cosa = -0,6; 270° ​<а<360

Answer 1

Объяснение:

$cos\alpha =0,6\ \ \ \ \ \ 270^0 \leq \alpha \leq 360^0\ \ \ \ tg\alpha =?\\sin^2\alpha+cos^2\alpha =1\\sin^2\alpha =1-cos^2\alpha =1-0,6^2=1-0,36=0,64.\\sin\alpha =б\sqrt{0,64}=б0,8.\ \ \ \ \ 270^0 \leq \alpha \leq 360^0\ \ \ \ \Rightarrow\\sin\alpha =-0,8.\\tg\alpha =\frac{sin\alpha }{cos\alpha }=\frac{-0,8}{0,6} =-\frac{4}{3} .$

Ответ: tgα=-4/3.

Answer 2

Calculating tga for cosa = -0.6 and 270° < a < 360°

To calculate the value of tga when cosa = -0.6 and 270° < a < 360°, we can use the trigonometric identity:

tga = sin(a) / cosa

First, we need to find the value of sin(a) for the given angle range.

Finding sin(a) for 270° < a < 360°

The sine function for the given angle range can be determined using the unit circle and the fact that sine is positive in the fourth quadrant.

The value of sin(a) for 270° < a < 360° is sin(a) = -1.

Now, we can calculate tga using the given values of cosa and sin(a).

Calculating tga

Using the formula tga = sin(a) / cosa, and substituting sin(a) = -1 and cosa = -0.6, we get:

tga = -1 / -0.6 = 1.6667

So, the value of tga for cosa = -0.6 and 270° < a < 360° is 1.6667.