Question

B) 4x2 + 4x + 1 = 0;​

Answer 1

Ответ:

4х²+4х+1=0

Д=16-16=0

х=-4/8=-1/2=-0.5

Объяснение:

Answer 2

To solve the quadratic equation 4x^2 + 4x + 1 = 0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our case, a = 4, b = 4, and c = 1. Plugging these values into the quadratic formula, we get:

x = (-4 ± √(4^2 - 4 * 4 * 1)) / (2 * 4) x = (-4 ± √(16 - 16)) / 8 x = (-4 ± √0) / 8

Since the discriminant (b^2 - 4ac) is equal to zero, we have a single solution:

x = -4 / 8 x = -1/2

Therefore, the solution to the equation 4x^2 + 4x + 1 = 0 is x = -1/2.