Question

2) 3(m-1)2+(m+2)(m2 — 2m+4)-(m+1) при m =-1/3​

Answer 1

Ответ:

3m²-6m+m³+8-m-1=m³+3m²-7m-1=(-1/3)³+3•(-1/3)²-7•(-1/3)-1=-1/27+1/3+7/3-1=-1/27+9/27+63/27-1=69/27-1=23/3-1=7 2/3-1=6 2/3

Answer 2

To find the value of the expression 3(m-1)^2 + (m+2)(m^2 - 2m + 4) - (m+1) when m = -1/3, we substitute -1/3 for m in the expression and simplify.

Let's calculate step by step:

Step 1: Substitute m = -1/3 into the expression: 3((-1/3) - 1)^2 + ((-1/3) + 2)((-1/3)^2 - 2(-1/3) + 4) - ((-1/3) + 1)

Step 2: Simplify the expression inside the parentheses: 3(-4/3)^2 + (5/3)(1/9 + 2/3 + 4) - (2/3)

Step 3: Simplify the expression inside the parentheses further: 3(16/9) + (5/3)(1/9 + 6/9 + 4) - 2/3

Step 4: Perform the multiplication: 48/9 + (5/3)(11/9) - 2/3

Step 5: Simplify the fractions: 16/3 + 55/27 - 2/3

Step 6: Find a common denominator for the fractions: (16/3)(9/9) + (55/27)(3/3) - (2/3)(9/9)

Step 7: Combine the fractions: 144/27 + 165/27 - 18/27

Step 8: Add the fractions: (144 + 165 - 18)/27

Step 9: Perform the addition: 291/27

Step 10: Simplify the fraction, if possible: 10 + 11/27

Therefore, the value of the expression 3(m-1)^2 + (m+2)(m^2 - 2m + 4) - (m+1) when m = -1/3 is 10 + 11/27.