Question

(a-28x)^2-48^2 (x+2)^2-x^2=4

Answer 1

Ответ:

$(a - 28x) {}^{2} - 48 {}^{2}$

$(a - 28x - 48) \times (a - 28x + 48)$

Объяснение:

(x+2)²-x²=4

x²+4x+4-x²=4

4x+4=4

4x=0

x=0

Answer 2

Let's solve the given equation step by step:

(a - 28x)^2 - 48^2 (x + 2)^2 - x^2 = 4

Expanding the squares:

(a - 28x)(a - 28x) - 48^2 (x + 2)(x + 2) - x^2 = 4

(a^2 - 56ax + 784x^2) - 48^2 (x^2 + 4x + 4) - x^2 = 4

a^2 - 56ax + 784x^2 - 48^2 (x^2 + 4x + 4) - x^2 = 4

Now, let's simplify the equation further:

a^2 - 56ax + 784x^2 - 48^2x^2 - 48^2(4x) - 48^2(4) - x^2 = 4

a^2 - 56ax + 784x^2 - 2304x^2 - 6144x - 768 - x^2 = 4

Now, combine like terms:

a^2 + (784 - 2304 - 1)x^2 - 56ax - 6144x - 768 = 4

a^2 - 1521x^2 - 56ax - 6144x - 768 = 4

Now, set the equation equal to zero by moving all terms to one side:

a^2 - 1521x^2 - 56ax - 6144x - 768 - 4 = 0

a^2 - 1521x^2 - 56ax - 6144x - 772 = 0

This is a quadratic equation in terms of 'x'. To solve it, you can use various methods such as factoring, completing the square, or using the quadratic formula.