Question

(x + 2)^3 – x^2(x + 5) – (x + 1)(x – 1) = 0

Answer 1

Ответ:

(x+2)³-x²(x+5)-(x+1)(x-1)=0

x³+6x²+12x+8-x³-5x²-x²+1=0

12x+9=0

12x=-9

x=-3/4

Answer 2

Ответ:

......

Объяснение:

сечас еще одно скину....

Answer 3

To solve the given equation:

Step 1: Expand the expressions. (x + 2)^3 = (x + 2)(x + 2)(x + 2) = (x^2 + 4x + 4)(x + 2) = x^3 + 2x^2 + 4x^2 + 8x + 4x + 8 = x^3 + 6x^2 + 12x + 8

-x^2(x + 5) = -x^3 - 5x^2

-(x + 1)(x - 1) = -(x^2 - 1) = -x^2 + 1

So the equation becomes: x^3 + 6x^2 + 12x + 8 - x^3 - 5x^2 - x^2 + 1 = 0

Simplifying further: (6x^2 - 6x^2) + (12x - x^2) + 8 + 1 = 0 11x - x^2 + 9 = 0

Step 2: Rearrange the equation. -x^2 + 11x + 9 = 0

Step 3: Solve the quadratic equation. To solve the quadratic equation, we can use factoring, completing the square, or the quadratic formula. In this case, let's use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = -1, b = 11, and c = 9:

x = (-(11) ± √((11)^2 - 4(-1)(9))) / (2(-1)) x = (-11 ± √(121 + 36)) / (-2) x = (-11 ± √157) / (-2)

Therefore, the solutions to the equation (x + 2)^3 – x^2(x + 5) – (x + 1)(x – 1) = 0 are:

x = (-11 + √157) / (-2) x = (-11 - √157) / (-2)

These are the approximate solutions.