Question

В аквапарке два бассейна квадратной формы. Стороны одного бассейна на 5 м больше, чем сторона другого бассейна. Известно, что площадь первого бассейна больше площади второго на 75 квадратных метров. Найдите сторону меньшего бассейна.

Answer 1

Ответ:

5 м.

Объяснение:

пусть х - сторона меньшего бассейна

тогда х+5 - сторона большего бассейна

площадь большего бассейна (х+5)^2

площадь меньшего бассейна х^2

вычитаем из большей меньшую и должны получить 75

(х+5)^2 - x^2=75

x^2+10x+25 - x^2=75

10x=75-25

10x=50

x=50:10

x=5

Answer 2

Problem Analysis

We are given two square-shaped pools in a water park. The side length of one pool is 5 meters longer than the side length of the other pool. The area of the first pool is 75 square meters larger than the area of the second pool. We need to find the side length of the smaller pool.

Solution

Let's assume that the side length of the smaller pool is x meters. According to the given information, the side length of the larger pool is x + 5 meters.

The area of a square is calculated by squaring its side length. Therefore, the area of the smaller pool is x^2 square meters, and the area of the larger pool is (x + 5)^2 square meters.

We are also given that the area of the first pool is 75 square meters larger than the area of the second pool. This can be expressed as the following equation:

x^2 = (x + 5)^2 - 75

To solve this equation, we can expand the right side and simplify:

x^2 = x^2 + 10x + 25 - 75

Simplifying further:

0 = 10x - 50

Now, let's solve for x:

10x = 50

x = 5

Therefore, the side length of the smaller pool is 5 meters.

Answer

The side length of the smaller pool is 5 meters.