Question

Log4x=-1 2x=8 log1/2(x+1)=-1

Answer 1

это полная задача или 3 отдельных задач?

Answer 2

To solve the given equations, let's take them one by one:

1. log4x = -1

To solve this equation, we need to rewrite it in exponential form. The logarithmic equation log base b of a equals c can be rewritten as b^c = a.

In this case, the equation log4x = -1 can be rewritten as 4^(-1) = x.

Since 4^(-1) is equal to 1/4, we have x = 1/4.

2. 2x = 8

Divide both sides of the equation by 2 to isolate x:

2x/2 = 8/2 x = 4

3. log(1/2)(x + 1) = -1

Rewrite the equation in exponential form:

(1/2)^(-1) = x + 1

Since (1/2)^(-1) is equal to 2, we have:

2 = x + 1

Subtract 1 from both sides of the equation:

2 - 1 = x 1 = x

Therefore, the solutions to the given equations are: x = 1/4, x = 4, and x = 1.