Question

(x+2)²-25=0................​

Answer 1

Ответ:

Объяснение:

(x+2)²-25=0

(x+2)²-5²-0

(x+2-5)(x+2+5)=0

(x-3)(x+7)=0

x-3=0     ;    x+7=0

x1=3            x=-7

x ∈  {-7; 3}

Answer 2

To solve the equation (x+2)² - 25 = 0, we can use the factored form of a difference of squares.

Step 1: Rewrite the equation (x+2)² - 25 = 0

Step 2: Apply the difference of squares formula [(x+2) + 5][(x+2) - 5] = 0

Step 3: Simplify (x+7)(x-3) = 0

Step 4: Set each factor equal to zero and solve for x x + 7 = 0 or x - 3 = 0

For x + 7 = 0: x = -7

For x - 3 = 0: x = 3

Therefore, the solutions to the equation (x+2)² - 25 = 0 are x = -7 and x = 3.