Question

(a-3)^2+(a+2)^2-2×(3-a)(a+2) ,если а=1/3

Answer 1

Ответ:

Для решения данного выражения, нужно подставить значение a=1/3 и выполнить арифметические операции в скобках:

(a-3)^2+(a+2)^2-2×(3-a)(a+2)

= (1/3 - 3)^2 + (1/3 + 2)^2 - 2×(3 - 1/3)(1/3 + 2)

= (-8/3)^2 + (7/3)^2 - 2×(8/3)×(7/3)

= 64/9 + 49/9 - 112/9

= 1/9

Таким образом, выражение (a-3)^2+(a+2)^2-2×(3-a)(a+2) при a=1/3 равно 1/9.

Answer 2

To evaluate the expression when a = 1/3, we substitute this value into the given expression:

(a-3)^2 + (a+2)^2 - 2*(3-a)*(a+2)

Substituting a = 1/3:

(1/3 - 3)^2 + (1/3 + 2)^2 - 2*(3 - 1/3)*(1/3 + 2)

Simplifying each term step by step:

(1/3 - 3)^2 = (-8/3)^2 = 64/9

(1/3 + 2)^2 = (7/3)^2 = 49/9

(3 - 1/3) = (9/3 - 1/3) = 8/3

(1/3 + 2) = (7/3)

Substituting these simplified values back into the expression:

64/9 + 49/9 - 2*(8/3)*(7/3)

Combining like terms:

113/9 - 2*(56/9)

Multiplying -2 by (56/9):

113/9 - 112/9

Subtracting the fractions:

1/9

Therefore, when a = 1/3, the expression (a-3)^2 + (a+2)^2 - 2*(3-a)*(a+2) evaluates to 1/9.