Question

(2y-1)(3y+2)-ву(у-4)​

Answer 1

Ответ:

2y-1•3y+2-by•y+4

2y-3y•1+2-4•by+y

-1y•-1•b•2y

-1y•2y•1b•-1

-2y•b•(-1)

Answer 2

To simplify the expression (2y-1)(3y+2)-v(u-4), we can use the distributive property and combine like terms:

(2y-1)(3y+2)-v(u-4) = 2y(3y+2) - 1(3y+2) - vu + 4v [Expanding using the distributive property] = 6y^2 + 4y - 3y - 2 - vu + 4v [Multiplying] = 6y^2 + y + 4 - vu + 4v [Combining like terms]

Therefore, the simplified expression is 6y^2 + y + 4 - vu + 4v.