Question

2х-3(х+4)<х-12 Розв'язати нерівність

Answer 1

$2x - 3(x + 4) < x - 12 \\ 2x - 3x - 12 - x < - 12 \\ - 2x < 0 \: \: \: \: \: | \div (- 2) \\ x > 0$

х ∈ (0; +∞)

Answer 2

Let's simplify the left side of the inequality using the distributive property:

2x - 3(x+4) = 2x - 3x - 12 = -x - 12

Now we can substitute this expression into the original inequality:

-x - 12 < x - 12

Let's isolate the variable to one side by adding x to both sides:

-x + x - 12 < x + x - 12 -12 < 2x - 12

Next, we'll add 12 to both sides:

-12 + 12 < 2x - 12 + 12 0 < 2x

Finally, we'll divide both sides by 2:

0/2 < 2x/2 0 < x

Therefore, the solution to the inequality is x > 0.