Question

A) 7(x-7)-3(x-3) b) 3n(n+c)+3c(n-c) в) a(2a^2-3n)-n(2n^2+a) g)3y^2(4y+1)-2y(y-2y)

Answer 1

1) 7x-49-3x+9
2) 3(n•(n+c)+c•(n-c))
3(n^2+2nc-c^2)
3)2a^3-3an-2n^3-an
2a^3-4an-2n^3
4) y•(12y^2+5y)
y•y•(12y+5)
y^2•(12y+5)

Answer 2

a)

7(x-7)-3(x-3)

= 7x - 49 - 3x + 9 // Distributing the 7 and -3 over the parentheses

= 4x - 40 // Combining like terms

Answer: 4x - 40

b)

3n(n+c)+3c(n-c)

= 3n^2 + 3nc + 3cn - 3c^2 // Distributing the 3 over the parentheses

= 3n^2 + 6nc - 3c^2 // Combining like terms

= 3(n^2 + 2nc - c^2) // Factoring out a 3

Answer: 3(n^2 + 2nc - c^2)

c)

a(2a^2-3n)-n(2n^2+a)

= 2a^3 - 3an - 2n^2a - na // Distributing the a and -n over the parentheses

= 2a^3 - 2n^2a - 3an - na // Rearranging terms

= 2a^3 - 2na(n + 1.5) // Factoring out a common factor of 2a and -2n

= 2a(a^2 - n(n + 1.5)) // Factoring out a common factor of -2n

Answer: 2a(a^2 - n(n + 1.5))

d)

3y^2(4y+1)-2y(y-2y)

= 12y^3 + 3y^2 - 2y^2 + 4y^2 // Distributing the 3y^2 and -2y over the parentheses

= 12y^3 + 5y^2 // Combining like terms

Answer: 12y^3 + 5y^2