Question

(2х+5)(7х-14)(1,6+0,4х)=0 4(х+4)-3(2х-6)+2(х-4)=0

Answer 1

4(x+4)-3(2x-6)+2(x-4)=0
4x+16-6x-18+2x-8=0
4x+2x-16x=8+18-16
Нет решений

Answer 2

To solve the first equation, we can use the zero product property, which states that if the product of two or more factors is equal to zero, then at least one of the factors must be zero. So we set each factor equal to zero and solve for x:

(2x+5)(7x-14)(1.6+0.4x) = 0

Factor out 2 from the first factor:

2(x + 2.5)(7x - 14)(1.6 + 0.4x) = 0

Now we can apply the zero product property:

2(x + 2.5) = 0 or 7x - 14 = 0 or 1.6 + 0.4x = 0

Solving each equation, we get:

x = -2.5 or x = 2 or x = -4

So the solutions to the first equation are x = -2.5, x = 2, and x = -4.

To solve the second equation, we can simplify the left-hand side by distributing the coefficients:

4(x + 4) - 3(2x - 6) + 2(x - 4) = 0

4x + 16 - 6x + 18 + 2x - 8 = 0

Simplifying further, we get:

x + 26 = 0

Subtracting 26 from both sides, we get:

x = -26

So the solution to the second equation is x = -26.