Question

16x-27y=20, 5x=18y=41,5 Решить систему уравнений.

Answer 1

5x=41.5 =>x=8.3
16*8.3-27y=20
132.8 - 27y = 20
112.8 = 27y
y=4.1(7)

Answer 2

There seems to be a typo in the second equation. I will assume you meant:

16x - 27y = 20

5x + 18y = 41

To solve this system of equations, we can use either substitution or elimination method. I will demonstrate the substitution method:

Solve for x in the second equation:

5x + 18y = 41

5x = 41 - 18y

x = (41 - 18y) / 5

Substitute this expression for x into the first equation:

16x - 27y = 20

16((41 - 18y) / 5) - 27y = 20

Multiplying both sides by 5 to eliminate the fraction:

16(41 - 18y) - 135y = 100

Expand and simplify:

656 - 288y - 135y = 100

-423y = -556

y = 4/3

Now we can substitute this value of y into either equation to solve for x. I will use the second equation:

5x + 18y = 41

5x + 18(4/3) = 41

5x + 24 = 41

5x = 17

x = 17/5

Therefore, the solution to the system of equations is:

x = 17/5, y = 4/3