Question

B^2-4c^2/b^2-4bc+4c^2 сократить дробь

Answer 1

$\frac{b^2-4c^2}{b^2-4bc+4c^2}= \frac{(b-2c)(b+2c)}{(b-2c)^2}= \frac{b+2c}{b-2c}$

Answer 2

To simplify the expression:

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B^2-4c^2
----------
b^2-4bc+4c^2

We can factor the numerator and denominator separately, then cancel out any common factors:

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B^2-4c^2    (B+2c)(B-2c)
---------- = -------------
b^2-4bc+4c^2  (b-2c)^2

Now we can cancel out the common factor of (B-2c) in the numerator and denominator, leaving:

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(B+2c)
------
(b-2c)

Therefore, the simplified expression is (B+2c)/(b-2c).