Question

1) (8c+3d)^2= 2) (5k+n)^2= 3) (5k-1)^2=

Answer 1

1) (8c+3d)^2=64c^2+9d^2

2) (5k+n)^2=25k^2+n^2

3) (5k-1)^2=25k-1

Answer 2

1. To expand (8c+3d)^2, we can use the formula for the square of a binomial: (a+b)^2 = a^2 + 2ab + b^2. Let's use this formula twice:

(8c+3d)^2 = (8c)^2 + 2(8c)(3d) + (3d)^2 = 64c^2 + 48cd + 9d^2

Therefore, (8c+3d)^2 = 64c^2 + 48cd + 9d^2.

2. To expand (5k+n)^2, we can use the same formula as above:

(5k+n)^2 = (5k)^2 + 2(5k)(n) + n^2 = 25k^2 + 10kn + n^2

Therefore, (5k+n)^2 = 25k^2 + 10kn + n^2.

3. To expand (5k-1)^2, we can use the same formula again:

(5k-1)^2 = (5k)^2 - 2(5k)(1) + 1^2 = 25k^2 - 10k + 1

Therefore, (5k-1)^2 = 25k^2 - 10k + 1.