Question

A)(2а+3b+4c)^2 Б)(y-2x+5)^2

Answer 1

А)(2а+3b+4c)²=4a²+9b²+16c²
б)(y-2x+5)²=y²+4x²+25
Так наверное)

Answer 2

A) To expand the expression (2a+3b+4c)^2, we can use the formula for the square of a binomial:

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(a + b)^2 = a^2 + 2ab + b^2

In this case, our binomial is 2a + 3b + 4c, so we can substitute a with 2a, b with 3b, and c with 4c:

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(2a + 3b + 4c)^2 = (2a)^2 + 2(2a)(3b) + (3b)^2 + 2(2a)(4c) + 2(3b)(4c) + (4c)^2
                  = 4a^2 + 12ab + 9b^2 + 16ac + 24bc + 16c^2

Therefore, (2a+3b+4c)^2 = 4a^2 + 12ab + 9b^2 + 16ac + 24bc + 16c^2.

B) To expand the expression (y-2x+5)^2, we can again use the formula for the square of a binomial:

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(a + b)^2 = a^2 + 2ab + b^2

In this case, our binomial is y - 2x + 5, so we can substitute a with y, and b with -2x + 5:

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(y - 2x + 5)^2 = y^2 + 2y(-2x + 5) + (-2x + 5)^2
               = y^2 - 4xy + 10y - 4x^2 + 20x + 25

Therefore, (y-2x+5)^2 = y^2 - 4xy + 10y - 4x^2 + 20x + 25.