Question

{3х-7у=11 {6х+7у=16 Методом сложения. 1 Смотреть ответ iBaHko iBaHko {9х=27 {7у=16-6х {х=3 {7у=-2 {х=3 {у=-2/7

Answer 1

To solve the system of equations using the method of addition, we need to add the two equations together in such a way that one of the variables is eliminated.

Multiplying the first equation by 2, we get:

6x - 14y = 22

Adding this to the second equation:

6x + 7y = 16

• 6x - 14y = 22

We get:

12x - 7y = 38

Now we have two equations:

3x - 7y = 11 (Equation 1) 12x - 7y = 38 (Equation 2)

We can eliminate y by subtracting Equation 1 from Equation 2:

(12x - 7y) - (3x - 7y) = 38 - 11

9x = 27

Dividing both sides by 9, we get:

x = 3

Substituting x = 3 into Equation 1, we get:

3(3) - 7y = 11

9 - 7y = 11

-7y = 2

y = -2/7

Therefore, the solution to the system of equations is:

x = 3, y = -2/7