Question

100-49х2у (5+х)2-9 (2а+7)2-(3а-5)2

Answer 1

100-49х^2у^2 =10²-(7xy)²=(10-7xy)(10+7xy)

(5+х)^2-9 =(5+x+3)(5+x-3)=(8+x)(2+x)

(2а+7)^2-(3а-5)^2=(2a+7+3a-5)(2a+7-3a+5)=(5a+2)(12-a)

Answer 2

Let's simplify this expression step by step:

1. We can simplify the term "49х2у" by multiplying 49, x, and y:

100 - 49х2у = 100 - 49xy2

2. We can simplify the expression "(5+х)2" by squaring the binomial:

(5+х)2 = (5+х)(5+х) = 25 + 10х + х2

3. We can simplify the expression "(2а+7)2" by squaring the binomial:

(2а+7)2 = (2а+7)(2а+7) = 4а2 + 28а + 49

4. We can simplify the expression "(3а-5)2" by squaring the binomial:

(3а-5)2 = (3а-5)(3а-5) = 9а2 - 30а + 25

Now we can substitute these simplified expressions back into the original expression and simplify further:

100 - 49xy2 - (25 + 10х + х2) - (4а2 + 28а + 49) - (9а2 - 30а + 25)

= 100 - 49xy2 - 25 - 10х - х2 - 4а2 - 28а - 49 - 9а2 + 30а - 25 (distributing the negative signs)

= -10х - х2 - 13а2 - 18а - 49 - 49xy2 (combining like terms)

Therefore, the simplified expression is -10х - х2 - 13а2 - 18а - 49 - 49xy2.