Question

(-7/8)^3+10*(3/4)^2 16 баллов

Answer 1

$\displaystyle \tt \bigg(-\frac{7}{8}\bigg)^{3}+10\cdot\bigg(\frac{3}{4}\bigg)^{2}=-\frac{343}{2^{9}}+\frac{90}{2^{4}}=\frac{90\cdot32-343}{2^{9}}=\frac{2537}{512}=4\frac{489}{512};$

Answer 2

Объяснение:

(-7/8)^3+10*(3/4)^2

- 343/512+10*9/16

-343/512+5*9/8

-343/512+45/8

2537/512

Answer 3

To solve this expression, we can start by simplifying each exponent and multiplication operation separately using the order of operations (PEMDAS):

1. Simplify (-7/8)^3:

(-7/8)^3 = -343/512

2. Simplify (3/4)^2:

(3/4)^2 = 9/16

3. Multiply 10 by 9/16:

10*(3/4)^2 = 10*(9/16) = 5.625

4. Add the results of step 1 and step 3:

(-7/8)^3 + 10*(3/4)^2 = -343/512 + 5.625

5. Convert the fraction to a decimal:

-343/512 = -0.669921875

6. Add the decimal result of step 5 to the decimal result of step 4:

-0.669921875 + 5.625 = 4.955078125

Therefore, (-7/8)^3 + 10*(3/4)^2 is approximately equal to 4.955078125.