Question

Срочноооооооооо ребят оч надо

Answer 1

$\displaystyle \tt \frac{9a^{2}-16b^{2}}{7a}\cdot\bigg(\frac{3b-4a}{4b^{2}-3ab}-\frac{3b+4a}{4b^{2}+3ab}\bigg)=\\\\\\=\frac{(3a-4b)(3a+4b)}{7a}\cdot\frac{(3b-4a)(4b^{2}+3ab)-(3b+4a)(4b^{2}-3ab)}{b^{2}(4b-3a)(4b+3a)}=\\\\\\=-\frac{12b^{3}-16ab^{2}+9ab^{2}-12a^{2}b-12b^{3}-16ab^{2}+9ab^{2}+12a^{2}b}{7ab^{2}}=\\\\\\=\frac{14ab^{2}}{7ab^{2}}=2$