Question

5x+(x-2)(x2+2x+4)-(-4+x3)=10

Answer 1

Ответ:

lyh;b c.ls jndtn

Объяснение:

Answer 2

Let's first simplify the expression on the left-hand side of the equation:

5x + (x - 2)(x^2 + 2x + 4) - (-4 + x^3) = 5x + (x^3 - 2x^2 + 4x) + (2x^2 - 4x + 8) + (4 - x^3) [using FOIL method to multiply (x - 2)(x^2 + 2x + 4)] = 5x + 6x^2 + 12 = 6x^2 + 5x + 12

So the equation becomes:

6x^2 + 5x + 12 = 10

Now, we can solve for x by bringing all the terms to one side:

6x^2 + 5x + 2 = 0

We can solve this quadratic equation using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 6, b = 5, and c = 2.

Plugging these values into the formula, we get:

x = (-5 ± sqrt(5^2 - 4(6)(2))) / 2(6) x = (-5 ± sqrt(25 - 48)) / 12 x = (-5 ± sqrt(-23)) / 12

Since the square root of a negative number is not a real number, the solutions to this equation are complex numbers:

x = (-5/12) ± (sqrt(23)/12)i

Therefore, the solutions to the original equation are:

x = (-5/12) + (sqrt(23)/12)i or x = (-5/12) - (sqrt(23)/12)i.