Question

(3x+1)(3x-2)-(3x-1)²=11

Answer 1

$9x ^{2} - 6x + 3x - 3 - 9x {}^{2} - 6x + 1 = 11$квадраты исчезли
-6x+3x-3-6x+1=11
-9x=14
x=14:9
x=1,5

Answer 2

(3х+1)(3х-2)-(3х-1)²=11
9х²-6х+3х-2-(9х²-6х+1)=11
9х²-6х+3х-2-9х²+6х-1=11
-6х+3х-2+6х-1=11
3х-3=11
3х=11+3
3х=14
х=
$\frac{14}{3}$
ответ:14/3

Answer 3

Let's start by simplifying the left side of the equation using the distributive property and algebraic rules for multiplying binomials:

(3x+1)(3x-2) - (3x-1)² = 9x² - 6x + 3x - 2 - (9x² - 6x + 1) = 9x² - 6x + 3x - 2 - 9x² + 6x - 1 (Note: the negative signs in front of the second binomial squared distribute to each term inside) = -3

So we have simplified the left side of the equation to -3. Now we can rewrite the original equation as:

-3 = 11

This is a contradiction because there is no value of x that makes -3 equal to 11. Therefore, there is no solution to the original equation.

In summary, the equation (3x+1)(3x-2)-(3x-1)²=11 has no solution.