Question

1)(a+3)= 2)(a+-B)^2=a^2+-2AB+B^2 3)(a+-B)^3=

Answer 1

1)(a+3)=a+3

2)(a+-B)^2=a^2+-2AB+B^2

3)(a+-B)^3=(a+b)3=a3+3a2b+3ab2+b3

       

Answer 2

(a±b)^3=a^3 ± 3a^2b + 3ab^2 ± b^3

Answer 3

3)(a+-B)^3 = a^3 + 3a^2(-B) + 3a(-B)^2 + (-B)^3

Expanding the expression using the binomial formula, we get:

3)(a+-B)^3 = a^3 + 3a^2(-B) + 3a(-B)^2 + (-B)^3 = a^3 - 3a^2B + 3aB^2 - B^3 = (a - B)^3 if we group the terms properly.

So, the expansion of (a+-B)^3 is a^3 - 3a^2B + 3aB^2 - B^3, which can also be written as (a - B)^3.