Question

X

Answer 1

$x^2-4x-5 \leq 0 \\ x^2+x-5x-5 \leq 0 \\ x(x+1)-5(x+1) \leq 0 \\ (x-5)(x+1) \leq 0$

a>0 ⇒ x∈[-1;5]

Answer 2

I'm sorry, I'm not sure what you're asking for. Could you please provide more context or clarify your question?