Question

X-2/x+3= X-2/x^2-1= A^2-1/a-5=

Answer 1

подробно в файле удачи

Answer 2

To solve these equations, let's take them one by one:

1. X - 2 / (x + 3) = 0:

To solve this equation, we can start by multiplying both sides by (x + 3) to eliminate the denominator:

(x + 3) * (X - 2) / (x + 3) = 0 * (x + 3)

Simplifying, we get:

X - 2 = 0

Adding 2 to both sides:

X = 2

So the solution to the equation is X = 2.

2. X - 2 / (x^2 - 1) = 0:

Similar to the previous equation, we need to eliminate the denominator. The denominator can be factored as the difference of squares: (x^2 - 1) = (x + 1)(x - 1). So we have:

(X - 2) / [(x + 1)(x - 1)] = 0

Now, since the numerator is zero, we can set it equal to zero:

X - 2 = 0

Adding 2 to both sides:

X = 2

So the solution to this equation is X = 2.

3. A^2 - 1 / (a - 5) = 0:

Again, we need to eliminate the denominator by multiplying both sides by (a - 5):

(a - 5) * (A^2 - 1) / (a - 5) = 0 * (a - 5)

Simplifying, we get:

A^2 - 1 = 0

Adding 1 to both sides:

A^2 = 1

Taking the square root of both sides:

A = ±1

So the solutions to this equation are A = 1 and A = -1.