Question

1) (×+10)(×-9)-(×-8)2=0 2)(3-y)(1-y2)+3y2=y3 3) (z-6)(z+5)-(z-2)z=30 4) 3a(a-3)+a(2-3a)=-100,59.

Answer 1

Смотри, сначала нужно раскрыть первые
две скобки, сейчас на примере первого покажу
12х-9х+10х-90-(х-8)2=0
умножаем скобку на 2, и раскрываем, меняя знаки в скобке на противоположные, так как перед скобкой стоит знак минус
2х-9х+10-90-2х+16=0
с иксом влево, без икса вправо
2х-9х-2х= -10+90-16
-9х=64
х= 64/ -9
х=7.1

Answer 2

1. (×+10)(×-9)-(×-8)2=0

Expanding the equation: (x+10)(x-9) - (x-8)2 = 0

Simplifying: (x^2 - 9x + 10x - 90) - (x^2 - 16x + 64) = 0

Combining like terms: x^2 - 9x + 10x - 90 - x^2 + 16x - 64 = 0

Simplifying further: 17x - 154 = 0

Adding 154 to both sides: 17x = 154

Dividing by 17: x = 9

Therefore, the solution to the equation is x = 9.

2. (3-y)(1-y^2) + 3y^2 = y^3

Expanding the equation: 3 - 3y - y^2 + y^3 + 3y^2 = y^3

Simplifying: 3 + y^3 - y^2 + 3y^2 - 3y = y^3

Combining like terms: 3y^2 - y^2 - 3y + y^3 - y^3 + 3 = 0

Simplifying further: 2y^2 - 3y + 3 = 0

The equation does not simplify further and does not have a clear solution.

3. (z-6)(z+5) - (z-2)z = 30

Expanding the equation: (z^2 - 6z + 5z - 30) - (z^2 - 2z) = 30

Simplifying: (z^2 - z - 30) - (z^2 - 2z) = 30

Distributing the negative sign: z^2 - z - 30 - z^2 + 2z = 30

Combining like terms: z^2 - z^2 + 2z - z - 30 = 30

Simplifying further: z - 30 = 30

Adding 30 to both sides: z = 60

Therefore, the solution to the equation is z = 60.

4. 3a(a-3) + a(2 - 3a) = -100.59

Expanding the equation: 3a^2 - 9a + 2a - 3a^2 = -100.59

Simplifying: 3a^2 - 3a^2 - 9a + 2a = -100.59

Combining like terms: -7a = -100.59

Dividing by -7: a = 14.37

Therefore, the solution to the equation is a = 14.37.