Question

Bq (q-1)=18 и bq (q+1)=54

Answer 1

выполним деление :

(bq(q-1))/(bq(q+1))=18/54 получаем

(q-1)/(q+1)=1/3 (пропорция, крест на крест)

3q-3=q+1

2q=4

q=2

подставим в любое данное нам уравнение q  и найдём b

b*2*1=18

2b=18

b=9

ответ: q=2, b=9

Answer 2

To solve the given equations:

1. Bq(q - 1) = 18
2. bq(q + 1) = 54

Let's solve each equation step by step:

1. Bq(q - 1) = 18

Expanding the equation, we have: Bq^2 - Bq = 18

Rearranging the equation, we get: Bq^2 - Bq - 18 = 0

Now, let's solve this quadratic equation using factoring or the quadratic formula.

By factoring: (Bq - 6)(Bq + 3) = 0

Setting each factor to zero and solving for Bq: Bq - 6 = 0 -> Bq = 6 Bq + 3 = 0 -> Bq = -3

So, we have two possible solutions: Bq = 6 and Bq = -3.

2. bq(q + 1) = 54

Expanding the equation, we have: bq^2 + bq = 54

Rearranging the equation, we get: bq^2 + bq - 54 = 0

Again, let's solve this quadratic equation using factoring or the quadratic formula.

By factoring: (bq + 9)(bq - 6) = 0

Setting each factor to zero and solving for bq: bq + 9 = 0 -> bq = -9 bq - 6 = 0 -> bq = 6

So, we have two possible solutions: bq = -9 and bq = 6.

Therefore, the possible values for the variables Bq and bq that satisfy the given equations are: Bq = 6, bq = -9 Bq = 6, bq = 6 Bq = -3, bq = -9 Bq = -3, bq = 6