Question

2x^2-3x-2/4x^2-1(дискриминанта)

Answer 1

2x²-3x-2=0
4x²-1≠0  4x²≠1  x²≠0,25  x≠0,5 и x≠-0,5
2x²-3x-2=0
D=b²-4ac
D=9+16=25
√25=5
x=3-5/4=-0,5
x=3+5/4=2
Ответ х=2

Answer 2

To find the discriminant of the quadratic expression (2x^2 - 3x - 2) divided by (4x^2 - 1), we need to determine the discriminants of both quadratic polynomials.

The discriminant (D) of a quadratic polynomial in the form ax^2 + bx + c is given by the equation D = b^2 - 4ac.

Let's calculate the discriminants for the numerator and denominator:

For the numerator (2x^2 - 3x - 2): a = 2, b = -3, c = -2 D_numerator = (-3)^2 - 4(2)(-2) = 9 + 16 = 25

For the denominator (4x^2 - 1): a = 4, b = 0, c = -1 D_denominator = (0)^2 - 4(4)(-1) = 0 + 16 = 16

Therefore, the discriminant of the expression (2x^2 - 3x - 2) divided by (4x^2 - 1) is D_numerator / D_denominator = 25 / 16.