Question

(х-2)в квадрате=3х-8 :)

Answer 1

(х-2)²=3х-8

(х²-2*2*х+4)=3х-8

х²-4х+4=3х-8

х²-4х-3х+4+8=0

х²-7х+12=0

по теореме виета

х1=4

х2=3

или через дискриминант

D=49-4*12=49-48=1

x1=(7-1)/2=6/2=3

x2=(7+1)/2=8/2=4

ответ 3;4

отметь,как лучшее,пожалуйста,очень нужно................

Answer 2

To solve the equation "(х-2)² = 3х-8," we can expand the squared term on the left side of the equation and then simplify:

(х-2)² = 3х-8

(x-2)(x-2) = 3x - 8

x² - 4x + 4 = 3x - 8

Now, let's collect like terms and simplify further:

x² - 4x - 3x + 4 + 8 = 0

x² - 7x + 12 = 0

To solve this quadratic equation, we can factor it:

(x - 3)(x - 4) = 0

Now we set each factor equal to zero:

x - 3 = 0 or x - 4 = 0

Solving these equations, we find:

x = 3 or x = 4

Therefore, the solutions to the equation (х-2)² = 3х-8 are x = 3 and x = 4.