Question

Sin2x=3sinxcosx

Answer 1

sin2x=3sinxcosx

2sinxcosx-3sinxcosx=0

-sinxcosx=0

sinx=o

x=Пn

cosx=0

x=П/2+Пn

 

 

 

Answer 2

To solve the equation sin(2x) = 3sin(x)cos(x), we can use trigonometric identities to simplify it.

First, let's recall the double angle identity for sine:

sin(2x) = 2sin(x)cos(x)

Substituting this into the equation, we have:

2sin(x)cos(x) = 3sin(x)cos(x)

Now, we can simplify by canceling out the common factor of sin(x)cos(x) on both sides:

2 = 3

Since the equation 2 = 3 is not true, there are no solutions to this equation. Therefore, there is no value of x that satisfies the equation sin(2x) = 3sin(x)cos(x).