Question

G(x)=√3x-x² у точках 0;1;3.

Answer 1

Что тут трудного? подставь цифру вместо Х:

G(0) = √3*0 - 0 = 0;

G(1)=√3*1-1² =√3-1

G(3)=√3*3-3² = 3√3 - 9

Answer 2

To find the values of the function G(x) = √(3x - x²) at the points 0, 1, and 3, we can substitute these values into the function and evaluate the results.

1. G(0): G(0) = √(3(0) - (0)²) = √(0 - 0) = √0 = 0

2. G(1): G(1) = √(3(1) - (1)²) = √(3 - 1) = √2

3. G(3): G(3) = √(3(3) - (3)²) = √(9 - 9) = √0 = 0

Therefore, the values of the function G(x) at the points 0, 1, and 3 are: G(0) = 0 G(1) = √2 G(3) = 0