Question

6sin (-P/4)-4COS(-P/3)-4 CTG^3(-4/6)

Answer 1

$6Sin(-\frac{\pi }{4})-4Cos(-\frac{\pi }{3})-4Ctg^{3}(-\frac{\pi }{6})=-6Sin\frac{\pi }{4}-4Cos\frac{\pi }{3}+4Ctg^{3} \frac{\pi }{6}=-6*\frac{\sqrt{2} }{2}-4*\frac{1}{2}+4*(\sqrt{3})^{3}=-3\sqrt{2}-2+12\sqrt{3}$

Answer 2

Let's break down the given expression step by step:

1. 6sin(-P/4): The sine function of any negative angle is equal to the negative sine of the corresponding positive angle. So, sin(-P/4) = -sin(P/4). Therefore, 6sin(-P/4) = 6*(-sin(P/4)) = -6sin(P/4).

2. -4COS(-P/3): The cosine function of any negative angle is equal to the cosine of the corresponding positive angle. So, cos(-P/3) = cos(P/3). Therefore, -4COS(-P/3) = -4*cos(P/3).

3. -4 CTG^3(-4/6): The cotangent function of any negative angle is equal to the negative cotangent of the corresponding positive angle. So, ctg(-4/6) = -ctg(4/6). The cube of a number remains the same whether it is positive or negative. So, (-4)^3 = -4^3 = -64. Therefore, -4 CTG^3(-4/6) = -4 * (-64) = 256.

Putting it all together, the given expression becomes:

-6sin(P/4) - 4cos(P/3) + 256