Question

{y=x-5 {x²=10+y² Help 1 Смотреть ответ tlq tlq Y=x-5 x²=10+y² x²=10+(x-5)² x=7/2 y=7/2-5 y=-3/2 x=7/2 y=-3/2 -3/2=7/2-5 (7/2)²=10+(-3/2)² -1.5=-1.5 12,25=12.25 х=7/2 y=-3/2

Answer 1

The solution you provided seems to be incorrect. Let's go through the equations step by step and solve them correctly.

The given equations are:

1. y = x - 5
2. x² = 10 + y²

Substitute the value of y from equation (1) into equation (2):

x² = 10 + (x - 5)²

Expand the squared term:

x² = 10 + (x² - 10x + 25)

Combine like terms:

x² = x² - 10x + 35

Rearrange the equation to have all terms on one side:

0 = -10x + 35

Solve for x by isolating the x-term:

10x = 35

x = 35/10

x = 3.5

Now substitute the value of x back into equation (1) to find y:

y = 3.5 - 5

y = -1.5

So, the solution to the system of equations is x = 3.5 and y = -1.5.