Question

Решите а б и в Срочно все в приложении

Answer 1

$5^{2 \sqrt{x} } + 5 \ \textless \ 5^{ \sqrt{x} +1 } +5^{ \sqrt{x} } \\ \\ odz:x \geq 0 \\ \\ (5^{ \sqrt{x} })^2 +5 \ \textless \ 5^{ \sqrt{x} } * 5 +5^ \sqrt{x} } \\ \\ t= 5^ \sqrt{x} } \\ \\ t^2 +5 \ \textless \ t*5+t \\ \\ t^2+5-6t\ \textless \ 0 \\ \\ \left(t-5\right)\left(t-1\right)\ \textless \ 0 \\ t =1 ,5$

t∈(1;5)

$\displaystyle 5^{ \sqrt{x} } \in (1;5) \\ \\ \left \{ {{5^{ \sqrt{x} }\ \textgreater \ 1} \atop {5^{ \sqrt{x} }\ \textless \ 5} \right. \\ \\ 5^{ \sqrt{x} }\ \textgreater \ 1 \\ 5^{ \sqrt{x} }\ \textgreater \ 5^0 \\ \sqrt{x} \ \textgreater \ 0 \\ \sqrt{x} =0 \\ x=0 \\ x\notin \mathbb{R} \\ \\ 5^{ \sqrt{x} }\ \textless \ 5 \\ 5^{ \sqrt{x} } \ \textless \ 5^1 \\ \sqrt{x} \ \textless \ 1 \\ x\ \textless \ 1 \\ \\ x\in ( - \infty ;0 ) \cup ( 0 ; 1) \\ \\ x \in(0,1)$

$\displaystyle ( \frac{1}{9} )^{|x-1|} \ \textgreater \ ( \frac{1}{27} )^{2x} \\ \\ 3^{-2*|x-1|} \ \textgreater \ 3^{-6x} \\ \\ -2*|x-1| \ \textgreater \ -6x \\ \\ -2*|x-1| +6x\ \textgreater \ 0 \\ \\ -2(x-1)+6x\ \textgreater \ 0 , x-1 \geq 0\\ -2x+2+6x\ \textgreater \ 0 \\ 4x+2\ \textgreater \ 0 \\ 4x\ \textgreater \ -2 \\ x \ \textgreater \ - \frac{1}{2} , x \geq 1 \\ \\ -2*(-(x-1))+6x\ \textgreater \ 0 ,x-1\ \textless \ 0\\ 2(x-1)+6x\ \textgreater \ 0 \\ 2x-2+6x\ \textgreater \ 0 \\ 8x-2\ \textgreater \ 0 \\ 8x\ \textgreater \ 2 \\ x\ \textgreater \ \frac{1}{4} , x\ \textless \ 1$
$\displaystyle \left \{ {{x\ \textgreater \ - \frac{1}{2},x \geq 1} } \atop {x\ \textgreater \ \frac{1}{4},x\ \textless \ 1 }} \right. \\ \\ \left \{ {{x\in[1,+\infty)} \atop {x\in(1 \frac{1}{4} ,1)}} \right. \\ \\ x\in( \frac{1}{4} ,+\infty)$