Question

Решите уравнение: 2/х-3=х+5/х^2-9

Answer 1

$\frac{2}{x-3} = \frac{x+5}{x^2-9}$
$\frac{2(x+3)}{(x-3)(x+3)} - \frac{x+5}{(x-3)(x+3)} =0$
$\frac{(2x+6)-(x+5)}{(x-3)(x+3)} =0$
$\frac{x-1}{(x-3)(x+3)} =0$
$x-1=0$
$x=1$