Question

Вес неподвижного блока 1Н. подвешенный к нему груз весит 5Н. Чему равно показания динамометра при подъёме груза?.. Решите плиз срочно нужно... Распишите Дано и решение...

Answer 1

Given:

- Weight of the stationary block = 1 N - Weight of the suspended load = 5 N

Solution:

To find the reading on the dynamometer when lifting the load, we need to consider the forces acting on the system.

1. Weight of the stationary block (1 N): This force acts downwards.

2. Weight of the suspended load (5 N): This force also acts downwards.

3. Tension in the string: This force acts upwards and is equal to the weight of the load (5 N) since the load is in equilibrium.

The reading on the dynamometer will be equal to the tension in the string, which is 5 N.

Therefore, the reading on the dynamometer when lifting the load is 5 N.

Please let me know if you need any further assistance!