Question

рабочее тело тепловой машины за цикл работы получает от нагревателя количество теплоты, равное 50 Дж и отдает холодильнику количество теплоты, равное 20 Дж. чему равен КПД тепловой машины

Answer 1

Calculation of Efficiency (КПД) of a Heat Engine

To calculate the efficiency (КПД) of a heat engine, we need to know the amount of heat received from the heat source (нагреватель) and the amount of heat rejected to the cold reservoir (холодильник). In this case, the heat received is 50 J (Дж), and the heat rejected is 20 J (Дж).

The efficiency (КПД) of a heat engine is defined as the ratio of the useful work output to the heat input. Mathematically, it can be expressed as:

КПД = (Useful work output) / (Heat input)

Since we are not given the value of the useful work output, we cannot calculate the exact efficiency. However, we can still discuss the concept of efficiency and its significance.

Efficiency is a measure of how effectively a heat engine converts heat energy into useful work. A higher efficiency means that a larger proportion of the heat input is converted into useful work, while a lower efficiency indicates that more heat is wasted.

In general, the efficiency of a heat engine is always less than 100% due to various factors such as friction, heat losses, and limitations imposed by the laws of thermodynamics. The maximum efficiency that can be achieved by a heat engine is determined by the Carnot cycle, which is a theoretical idealization.

To calculate the exact efficiency of the heat engine in this specific scenario, we would need additional information, such as the value of the useful work output or the type of heat engine being considered.

Please let me know if there is anything else I can help you with!