Question

Магнит массой 50 г прилип к железной вертикальной стенке. Чтобы магнит равномерно скользил вниз, к нему необходимо приложить направленную вертикально вниз силу 2 Н. Какую минимальную силу надо приложить к магниту, чтобы он равномерно скользил вверх?

Answer 1

Finding the Minimum Force Required for the Magnet to Slide Upward

To find the minimum force required for the magnet to slide upward, we need to consider the forces acting on the magnet.

The force of gravity acting on the magnet is given by its weight, which can be calculated using the formula:

Weight = mass x acceleration due to gravity

Given that the mass of the magnet is 50 g (0.05 kg) and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the weight of the magnet:

Weight = 0.05 kg x 9.8 m/s^2

Now, since the magnet is sliding upward, we need to apply a force in the opposite direction to counteract the force of gravity. This force should be equal to or greater than the weight of the magnet to ensure it moves upward.

Therefore, the minimum force required to make the magnet slide upward is equal to its weight, which is calculated as:

Minimum Force = Weight = 0.05 kg x 9.8 m/s^2

Calculating this value gives us the minimum force required to make the magnet slide upward.

Please note that the provided information does not specify any additional forces or factors that may affect the motion of the magnet. The calculation assumes a simplified scenario where only the force of gravity and the applied force are considered.

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