Question

Проволочная спираль, сопротивление которой 55 ом включена в сеть напряжением 220 В. Какое кол-во теплоты выделяет эта спираль за 1 мин. за 30 мин. Кол-во теплоты записать в кал. и в кДж

Answer 1

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Answer 2

Calculation of Heat Generated by the Wire Coil

To calculate the amount of heat generated by the wire coil, we need to use the formula:

Q = I^2 * R * t

Where: - Q is the heat generated (in joules) - I is the current flowing through the wire coil (in amperes) - R is the resistance of the wire coil (in ohms) - t is the time for which the current flows (in seconds)

Given: - Resistance (R) = 55 ohms - Voltage (V) = 220 volts

To find the current (I), we can use Ohm's Law:

I = V / R

Let's calculate the current flowing through the wire coil:

I = 220 V / 55 Ω = 4 A

Now, we can calculate the heat generated by the wire coil for different time intervals.

Heat Generated in 1 Minute

Let's calculate the heat generated in 1 minute (60 seconds):

Q = (4 A)^2 * 55 Ω * 60 s = 52800 J

Therefore, the wire coil generates 52800 joules of heat in 1 minute.

Heat Generated in 30 Minutes

Let's calculate the heat generated in 30 minutes (1800 seconds):

Q = (4 A)^2 * 55 Ω * 1800 s = 3168000 J

Therefore, the wire coil generates 3168000 joules of heat in 30 minutes.

Conversion to Calories and Kilojoules

To convert the heat generated from joules to calories, we can use the conversion factor:

1 calorie = 4.184 joules

To convert the heat generated from joules to kilojoules, we can use the conversion factor:

1 kilojoule = 1000 joules

Let's convert the heat generated to calories and kilojoules:

- Heat generated in 1 minute: 52800 J - Calories: 52800 J / 4.184 J/cal = 12631.79 cal - Kilojoules: 52800 J / 1000 J/kJ = 52.8 kJ

- Heat generated in 30 minutes: 3168000 J - Calories: 3168000 J / 4.184 J/cal = 756916.09 cal - Kilojoules: 3168000 J / 1000 J/kJ = 3168 kJ

Therefore, the heat generated by the wire coil is approximately: - 12631.79 calories in 1 minute - 756916.09 calories in 30 minutes - 52.8 kilojoules in 1 minute - 3168 kilojoules in 30 minutes

Please note that these calculations assume that the resistance remains constant and there are no other factors affecting the heat generation.