Question

Расход энергии в электрической лампе при силе тока 1 А в течении 5 ч составляет 20000кДЖ. Чему равно сопротивление ламы?

Answer 1

Вот:

Надеюсь это, если не то , то прости

Answer 2

Calculation of Resistance in the Electric Lamp

To calculate the resistance of the electric lamp, we can use Ohm's Law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I). In this case, we are given the current (1 A) and the energy consumption (20,000 kJ) over a period of 5 hours.

First, we need to convert the energy consumption from kilojoules (kJ) to joules (J). Since 1 kJ is equal to 1000 J, the energy consumption is 20,000 kJ * 1000 J/kJ = 20,000,000 J.

Next, we can calculate the power (P) consumed by the electric lamp using the formula: power = energy / time. In this case, the power is 20,000,000 J / 5 hours = 4,000,000 J/hour.

Now, we can use Ohm's Law to calculate the resistance. Ohm's Law states that resistance (R) is equal to voltage (V) divided by current (I). Since we are given the current (1 A), we need to find the voltage.

The power (P) consumed by the electric lamp can also be calculated using the formula: power = voltage * current. Rearranging the formula, we get: voltage = power / current. Substituting the values, we have: voltage = 4,000,000 J/hour / 1 A = 4,000,000 V.

Finally, we can calculate the resistance using Ohm's Law: resistance = voltage / current. Substituting the values, we get: resistance = 4,000,000 V / 1 A = 4,000,000 ohms.

Therefore, the resistance of the electric lamp is 4,000,000 ohms.

Please note that the above calculation assumes a constant current throughout the 5-hour period and does not take into account any variations in the lamp's resistance due to factors such as temperature.