Question

Определите кинетическую энергию тела массой 1 кг брошенного со скоростью 20 м/с под углом 30° к горизонту, в конце первой секунды его движения.

Answer 1

Это балистика. Есть ряд формул, которые следует знать) без них задачи не решить

Answer 2

Calculation of Kinetic Energy

To calculate the kinetic energy of an object, we can use the formula:

Kinetic Energy (KE) = (1/2) * mass * velocity^2

Given: - Mass of the object (m) = 1 kg - Velocity of the object (v) = 20 m/s

Using the formula, we can calculate the kinetic energy:

KE = (1/2) * m * v^2

KE = (1/2) * 1 kg * (20 m/s)^2

KE = (1/2) * 1 kg * 400 m^2/s^2

KE = 200 Joules

Therefore, the kinetic energy of the object is 200 Joules.

Calculation at the End of the First Second

To determine the position of the object at the end of the first second, we need to consider the horizontal and vertical components of its motion.

The horizontal component of the velocity remains constant throughout the motion and is given by:

v_x = v * cos(theta)

where: - v_x is the horizontal component of velocity - v is the initial velocity of the object - theta is the angle between the velocity vector and the horizontal axis

Given: - Initial velocity (v) = 20 m/s - Angle (theta) = 30 degrees

Using the formula, we can calculate the horizontal component of velocity:

v_x = 20 m/s * cos(30 degrees)

v_x = 20 m/s * 0.866

v_x = 17.32 m/s

The vertical component of the velocity changes due to the acceleration due to gravity. The acceleration due to gravity (g) is approximately 9.8 m/s^2.

The vertical component of velocity at the end of the first second can be calculated using the formula:

v_y = v * sin(theta) - g * t

where: - v_y is the vertical component of velocity - v is the initial velocity of the object - theta is the angle between the velocity vector and the horizontal axis - g is the acceleration due to gravity - t is the time

Given: - Initial velocity (v) = 20 m/s - Angle (theta) = 30 degrees - Acceleration due to gravity (g) = 9.8 m/s^2 - Time (t) = 1 second

Using the formula, we can calculate the vertical component of velocity:

v_y = 20 m/s * sin(30 degrees) - 9.8 m/s^2 * 1 second

v_y = 20 m/s * 0.5 - 9.8 m/s^2

v_y = 10 m/s - 9.8 m/s^2

v_y = 0.2 m/s

Therefore, at the end of the first second, the horizontal component of velocity is 17.32 m/s and the vertical component of velocity is 0.2 m/s.

Please let me know if there is anything else I can help you with!